Question 1126659
Assuming this is what you mean
{{{6^2/x+4^1/x=10/3}}} * {{{12^1/x }}}
:
{{{36/x+4/x}}} = {{{120/(3x)}}}
:
{{{40/x}}} = {{{120/(3x)}}}
cancel 3
{{{40/x}}} = {{{40/x}}}
no unique solution for x, (x<>0)