Question 1126527
express the ff as a single logarithm.
{{{-log(4) + 3*log(x-3) + 2*log(y) - (1/2)*log(4)}}}
use exponents
{{{-log((4)) + log(((x-3)^3)) + log((y^2)) - log((4^(1/2)))}}}
4 with an exponent of 1/2 is 2
{{{-log((4)) + log(((x-3)^3)) + log((y^2)) - log((2))}}}
combine
{{{log(((x-3)^3*y^2)/(4*2)))}}} = {{{log((((x-3)^3*y^2)/(8))))}}}