Question 1126365

if you have combinations and permutations, then

(b) C6, 4.

{{{6C4= (6!)/(2! 4!)=15}}}

(c) P7, 7.

{{{7P7=(7!)/((7 - 7)!)=5040}}}

(d) C8, 8.
 
{{{8C8=(8!)/(0! 8!)=1}}}