Question 101904
/3x^2 - 3/48x^2 - 2/48x^2  (radical equations)
:
Assume you mean:
{{{sqrt(3x^2)}}} - {{{3sqrt(48x^2)}}} - {{{2sqrt(48x^2)}}}
;
{{{sqrt(48x^2)}}}'s are like terms so just do the math:
you then have;
{{{sqrt(3x^2)}}} - {{{5sqrt(48x^2)}}}
:
Factor inside the radicals:
{{{sqrt(3*x*x)}}} - {{{5sqrt(3*4*4*x*x)}}}
:
Extract the squares:
{{{x*sqrt(3)}}} - {{{5*4*x*sqrt(3)}}}
:
{{{x*sqrt(3)}}} - {{{20x*sqrt(3)}}}
:
Like terms again, do the math and you have
{{{-19x*sqrt(3)}}}
: