Question 1126425
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Change the "2" to "log base 10 of some number": 2 = log base 10 of 100.<br>
Since the problem is in the standard base 10, we don't need to keep writing "base 10".  Then<br>
{{{log((x+4)) = log((100))+log((x))-log((20)) = log(((100*x)/20)) = log((5x))}}}<br>
Then, since log(A)=log(B) means A=B,<br>
{{{x+4 = 5x}}}
{{{4x = 4}}}
{{{x = 1}}}<br>