Question 1126344

check the sum of elements in {{{p(X)}}} first

If the following is a probability distribution, the sum of elements in {{{p(X)}}}'s  must be equal {{{1}}}.

{{{0.03+0.200+0.444+0.296=0.97}}}

So, it is {{{NOT}}} a probability distribution. The sum of the {{{p(X)}}}'s is not {{{1}}}, since {{{0.97 <>1.000}}}.