Question 1126362

 Find the common ratio and write out the first four terms of the geometric sequence

{{{9^(n+3)/10}}}

={{{(9^4/10)9^(n-1)}}}

={{{(6561/10)9^(n-1)}}}

={{{(656.1)9^(n-1)}}}

compare to {{{a[n]= a[1]*r^(n-1)}}}, you see that first term is {{{a[1]=656.1}}} and the common ratio is {{{r=9}}}



{{{a[1]=656.1}}}
{{{a[2]=656.1*r^1=656.1*9=5904.9}}}
{{{a[3]=656.1*r^2=656.1*81=53144.1}}}
{{{a[4]=656.1*r^3=656.1*729=478296.9}}}