Question 1126289
let d be the number of dimes, then
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number of quarters is 2d
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let n be the number of nickels, then
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d +n +2d = 500
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1) n +3d = 500
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2) 0.05n + 0.10d +0.25(2d) = 88.00
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solve equation 1 for d
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3d = (500 - n)
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d = (500 - n)/3
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substitute for d in equation 2
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0.05n +0.10((500 - n)/3) +0.50((500 - n)/3) = 88.00
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multiply both sides of = by 3
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0.15n +50 -0.10n +250 -0.50n = 264.00
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-0.45n = -36
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n = 80
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There are 80 nickels
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check the answer
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500 - 80 = 420
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then there are 140 dimes and 280 quarters
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0.05(80) + 0.10(140) + 0.25(280) = 88.00
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4 +14 +70 = 88.00
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88.00 = 88.00
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answer checks
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