Question 1126191
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It is clear even without my explanations that for n >= 10 the cube of n,  {{{n^3}}},  has MORE digits than  the square  {{{n^2}}}.


Therefore, only 1-digit numbers must be checked

n     n^2     n^3
-----------------

0     0        0    (*)

1     1        1    (*)

2     4        8    (*)

3     9       27

4     16      64    (*)

5     25     125

6     36     256

7     49

8

9

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For your convenience, I marked the favorable numbers by (*), so you can calculate the ANSWER on your own.
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