Question 1126127
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Let *[tex \Large x] represent the number of $80 tickets, *[tex \Large y] the number of $60 tickets, and *[tex \Large z] represent the number of $50 tickets.


We know that


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ +\ z\ =\ 1000]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ 2z\ +\ 400]


which is to say


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ -\ 2z\ =\ 400]


and finally


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 8x\ +\ 6y\ +\ 5z\ =\ 6280]


Solve the 3X3 system for *[tex \Large x,\ \ ]*[tex \Large y, \ \ ] and *[tex \Large z] by any convenient means.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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