Question 1126092
Need assistance please!

I am asked to Solve a quadratic equation and show check of the potential answer's. Additionally, any excluded values should also be identified.

a-4/a^2+5a -2/a+5=1/a^3+7a^2+10a

I worked through the problem and came up with a solution of a=-3.

Performing the check has me confused as I believe this is what will tell me if the values are excluded?

I did (-3+3)^2 which =0

I know 0 is an excluded value, but is the above the right approach or am I doing something wrong?

Thank you!
<pre>Your answer, - 3 is CORRECT!! Good work!
{{{matrix(1,3, (a - 4)/(a^2 + 5a) - 2/(a + 5), "=", 1/(a^3 + 7a^2 + 10a))}}}
{{{matrix(1,3, (a - 4)/a(a + 5) - 2/(a + 5), "=", 1/a(a^2 + 7a + 10))}}} ------------- Factoring denominators that can be factored
{{{matrix(1,3, (a - 4)/a(a + 5) - 2/(a + 5), "=", 1/(a(a + 5)(a + 2)))}}} ------------- Factoring denominator on right, further
We now see, based on the most previous equation that {{{matrix(3,1, a <>0, a <> - 5, a <> - 2)}}}
Since the answer that you got - which is correct - is NONE of the above restricted values for "a", then we can say that it is indeed the solution.
The only thing I see here that's wrong is your calculation of {{{(a + 3)^2}}}.
It's not part of any of the DENOMINATORS, so that's not how you check to see if your answer is CORRECT!