Question 1126091

the length: {{{L}}} 
 the width: {{{W}}}

if the length of rectangular sign is {{{12}}} less than twice the width, we have

{{{L=2W-12}}} ...eq.1

if its perimeter is {{{114}}} feet, we have

{{{2(L+W)=114}}}

{{{L+W=114/2}}}

{{{L+W=57}}}

{{{L=57-W}}}....eq.2

from eq.1 and eq.2 we have

{{{2W-12=57-W}}}.......solve or {{{W}}}

{{{2W+W=57+12}}}

{{{3W=69}}}

{{{highlight(W=23)}}} meters

go back to {{{L=2W-12}}} ...eq.1 and plug in {{{W}}} 

{{{L=2*23-12}}} 

{{{highlight(L=34)}}} meters