Question 102155
1.2(x+4)-2.5(3y-2) = 2
Multiply thru by 10 to get rid of the decimals:
12(x+4) - 25(3y-2) = 20
12x+48-75y+50 = 20
12x-75y= -78
Divide thru by 3 to get:
4x - 25y = -26
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(4/5)(3x-5)+ (3/2)(3y-4) = -10 
Multiply thru by 10 to get rid of the denominators:
8(3x-5) + 15(3y-4) = -100
24x-40+45y-60 = -100
24x+45y = 0
8x+15y = 0
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Solve this system of equations:
1st: 4x - 25y = -26
2nd: 8x + 15y = 0
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Multiply 1st by "2" to get:
3rd: 8x - 50y = -52
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Subtract 2nd from 3rd to get:
-65y = -52
y = (4/5) or 0.8
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Substitute into 2nd to solve for "x"
8x + 15(4/5) =0
8x + 12 = 0
x = -1.5
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Final solution: 
x= -1.5
y= 0.8
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Check the answer in 1.2(x+4)-2.5(3y-2) = 2
1.2((-1.5)+4)-2.5(3*0.8-2) = 2
1.2(2.5) - 2.5(0.4) = 2
3 - 1 = 2
2 = 2
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Cheers,
Stan H.