Question 1125789
For this explanation, please refer to the Venn diagram completed below with sections A, B, C, D, E, F and G.
<br>We start by filling in section A, which represents the intersection of all three events, P(E &#8745; F &#8745; G) = 0.3.
<br>Then we go to each of the other intersections of exactly two events. Since section A = 0.3 is part of the sections representing E&#8745;F, E&#8745;G and F&#8745;G, we must subtract 0.3 from each of those double intersections, thereby getting:
<br>Section B = P(E&#8745;F) = 0.35-.3 = .05
Section C = P(E&#8745;G) = 0.39-.3 = .09
Section D = P(F&#8745;G) = 0.4-.3 = .1
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Now you fill in the remaining sections, which is the necessary difference to make each full circle add up to P(E), P(F) and P(G). 
Section E = P(E) - (.05 + .3 + .09) = .65 - .44 = .21
Section F = P(F) - (.05 + .3 + .1) = .57 - .45 = .12
Section G = P(G) - (.3 + .09 + .1) = .55 - .49 = .06

 *[illustration Venn_EFG]

Now add up every number in the 7 sections = 
P(E &#8746; F &#8746; G) = .93