Question 1125839

given:

 the base of a triangle measures {{{a=12in}}}
 the area of the triangle is {{{A=42in^2}}}

 find the height: {{{h}}}

{{{A=(1/2)a*h}}}

{{{2A=a*h}}}

{{{h=2A/a}}}...plug in given values

{{{h=(2*42in^2)/12in}}}

{{{h=(cross(2)*42in^cross(2))/cross(12)6cross(in)}}}

{{{h=(42in)/6}}}

{{{h=7in}}}