Question 1125806
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Let x is invested at 10%.  The annual interest of this investment is 0.1*x dollars.


The the investment at 6%  is  (30000-x),  and its generates the annual interest of 0.06(30000-x) dollars.


Your equation is


    <U>interest</U> + <U>interest</U>       = <U>total interest</U>,    or


    0.1x     + 0.06*(30000-x) = 2360    dollars.


    0.1x + 0.06*30000 - 0.06x = 2360


    0.1x - 0.06x = 2360 - 0.06*30000


    x = {{{(2360 - 0.06*30000)/(0.1-0.06)}}} = 14000.


<U>Answer</U>.  $14000 was invested at 10%  and  the rest,  (30000-14000) = 16000 dollars were invested at 6%.


<U>Check</U>.   0.1*14000 + 0.06*16000 = 2360 dollars.    ! Correct !
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It is a standard and typical problem on investments.


If you need more details,  &nbsp;or if you want to see other similar problems solved by different methods, &nbsp;look into the lesson 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.