Question 101876
How do you solve
{{{(2n^2-9n+4)/(2n^2-n)}}}*{{{(n^3)/(n-4)}}}
:
Factor what you can:
{{{((2n-1)(n-4))/(n(2n-1))}}} *{{{(n^3)/(n-4)}}}
:
Look at it now. that (n-4) & (2n-1) cancels, jumps out at you. Also n into n^3, results:
{{{n^2}}} is the final answer