Question 1125579
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If E and F are two disjoint events in S with P(E) = 0.6 and P(F) = 0.1, find P(E ∪ F), P(EC), P(E ∩ F), P((E ∪ F)C), and P((E ∩ F)C). 


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P(E &#8746; F) = P(E) + P(F) = 0.6 + 0.1 = 0.7.
	 	 
P(EC)          = 1 - P(E) = 1 - 0.6 = 0.4.

P(E &#8745; F) = 0.

P((E &#8746; F)C) = 1 - P(E) - P(F) = 1 - 0.6 - 0.1 = 0.3.

P((E &#8745; F)C) = 1 - P(E &#8745; F) = 1 - 0 = 1.
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