Question 1125530
If (6;-2) is a point on the circumference of a circle with the centre at the origin then the equation of the circle is.....? 
<pre><b><u>WRONG, WRONG, again and AGAIN</u>!! ======> {{{cross(highlight((x-6)^2+(y+2)^2=40))}}} by someone with ARITHMETIC in his name</b>! Isn't this a JOKE? I know MANY will agree with me!
Have another person give you a different answer or use your book and/or internet to find the equation.