Question 1125526
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At most 2 persons are selected = <U>0 selected</U> + <U>1 selected</U> + <U>2 selected</U>.


P(0 selected) = {{{(1-0.32)^5}}} = {{{0.68^5}}} = 0.14539.


P(1 selected) = {{{C[5]^1*0.68^4*0.32}}} = {{{5*0.68^4*0.32}}} = 0.34210.


P(2 selected) = {{{C[5]^2*0.68^3*0.32^2}}} = {{{10*0.68^3*0.32^2}}} = 0.32198.



P(At most 2 persons are selected) = 0.14539 + 0.34210 + 0.32198 = 0.8095 = 80.95%.
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Solved.