Question 1125505
{{{tan(theta) = -15 }}}

{{{tan(theta)}}} is negative in II and IV quadrant, so we can find only angles from II quadrant because is given to find all angles {{{theta}}} between {{{0}}}° and {{{180}}}° ( in your case it will be angle greater than {{{90}}}° and less than {{{180}}}°)

so, solution is:

{{{theta=tan^-1(-15) =93.81}}}°