Question 102037
 
Find the slope of the perpendicular line.

For two lines to be perpendicular, their slopes are negative reciprocals of each other.  

{{{m[2] = -1/m[1]}}} 
Or in your case 
{{{m[2] = -(1/(-11/12))}}} 
{{{m[2] = 12/11}}} 
Since you didn't specify any points for the perpindicular line to pass through, you can choose the origin (0,0) as a point on the line. The slope-intercept form of the line equation is 
{{{y=m[2]*x+b[2]}}}
{{{0=(12/11)*0+b[2]}}} Slope is 12/11 from above and (0,0) is a point on the line. 
{{{b[2]=0}}} Solve for {{{b[2]}}}. 
{{{y=(12/11)*x}}}
Graphically : 
{{{ graph( 300, 300, -5, 5,  -5,  5, (-11/12)*x+25/6,(12/11)*x)}}}