Question 1125428
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Let x be the amount invested at 6%, in dollars.

Then the amount invested at 5% is the rest (1600-x) dollars.



Your basic equation is THIS:


    <U>interest</U> + <U>interest</U>      = <U>total interest</U>,    or


    0.06*x   + 0.05*(1600-x) = 89.


    0.06x + 0.05*1600 - 0.05x = 89


    0.01x = 89 - 0.05*1600  ====>  x = {{{(89 - 0.05*1600)/0.01}}} = 900.


<U>Answer</U>.  $900 should be invested at 6%  and the rest  1600 - 900 = 700 dollars should be invested at 5%.


<U>Check</U>.   0.05*700 + 0.06*900 =  89 dollars.   ! Correct !
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To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.