Question 1125317
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Here is an alternative to the usual algebraic solution method used by the other tutor.<br>
For many (probably most) students the algebraic method is easier to use.  But try this one and see if it works for you.<br>
The ratio of the speeds of the two planes is 496:558 = 8:9.  Since the distances are the same, the ratio of times is 9:8.<br>
So we can let 9x be the amount of time the first plane took and 8x be the amount of time the second plane took.<br>
Then since the difference in flight times was half an hour, 9x-8x=x = .5 hours.<br>
Then the flight time for the first plane was 9x=4.5 hours and the time for the second plane was 8x=4 hours.