Question 1125285
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QS = ST and RS = SU, both by defn of midpoint, hence segments QS and ST are congruent and RS and SU are congruent.  Angle QSR congruent Angle UST because they are vertical angles.  Hence, triangle QSR is congruent to triangle UST.  Then angle TUS is congruent to angle QRS by CPCT.  Then segment QR parallel to segment TU by equal opposite interior angles of a transversal.  You can't actually prove anything about line QR or line TU because QR and TU are line segments, NOT lines.  You can claim that the line CONTAINING segment QR is parallel to the line CONTAINING the segment TU.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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