Question 1125308
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ N(t)\ =\ a\(1\ -\ e^{-0.5t} \)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{dN}{dt}\ =\ \frac{a}{2}e^{-0.5t}]


The rest is just arithmetic.  Whichever derivative evaluates to the larger number is the point in time where the word is spreading faster.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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