Question 1125210
If n is number of increments of 50 dollars, then price becomes  650-50n.

If use x for counting each increment of $50 then x=50n; and number of tickets is 50+10n.

<pre>
PRICE       TICKETS
650-x       50+x/5
</pre>

Revenue is  {{{y=(650-x)(50+x/5)}}}.

Maximum revenue is exactly in the middle of the two zeros of y.


Zeros are  650 and  -250.
Exact Middle of the two zeros:   200 dollars decrease from  $650.  Price there for max revenue, $450, best ticket price.
Max Revenue:  $40500.