Question 1125170
{{{f(x)=-(8 (x+62)(x-29))/((x-59)(x-37)(x-29))}}}

holes: 
To find the holes in a rational function, you must factor the numerator and denominator of the rational function and see if there are any common factors, then simplify it. If there is the same factor in  the numerator and denominator, there is a hole.

you are given
{{{f(x)=-(8 (x+62)(x-29))/((x-59)(x-37)(x-29))}}} which is already factored and you can see there is {{{(x-29)}}} to simplify,  that is common factor, means there is a hole at {{{x=29}}}

find {{{y}}} coordinate, plug in {{{x=29}}}
{{{y=-(8 (29+62)(29-29))/((29-59)(29-37)(29-29))}}}
{{{y=-(8 (91)(0))/((87)(66)(0))}}}
{{{y=0}}}

hole is at ({{{29}}},{{{0}}})


and vertical asymptotes:
{{{f(x)=-(8 (x+62)(x-29))/((x-59)(x-37)(x-29))}}}...first simplify


{{{f(x)=-(8 (x+62))/((x-59)(x-37))}}}


I'll find any vertical asymptotes, by setting the denominator equal to zero and solving:

 {{{(x-59)(x-37)=0}}}

and it is

{{{(x-59)=0}}}->{{{x=59}}}}
{{{(x-37)=0}}}->{{{x=37}}}}

a vertical asymptotes are at {{{x=59}}}, and{{{x=37}}}

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