Question 1125130
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I assume that your formula is    h(x) = {{{1/sqrt(2x+1)}}} + {{{sqrt(2x+1)}}}.



To avoid ambiguity,  you should write it as    h(x) = (1/sqrt(2x+1)) + sqrt(2x+1)


using PARENTHESES to show the fraction correctly  (if the formula is as I assumed).



<pre>
    f(x) = 2x+1;


    g(x) = {{{1/sqrt(x)}}} + {{{sqrt(x)}}}.



First the function  f(x)  converts  "x"  into  "2x+1";


Then the function  g(x)  converts  "2x+1"  into  {{{1/sqrt(2x+1)}}} + {{{sqrt(2x+1)}}}.
</pre>