Question 1124936
"Find three positive consecutive integers such that the product of the smallest and largest is 17 more than three times the median integer." 


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{{{system(x, x+1, x+2)}}}
and
{{{x>0}}}


{{{x(x+2)=17+3(x+1)}}}------solve this.

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{{{x^2+2x=3x+3+17}}}
{{{x^2-x-20=0}}}
{{{(x+4)(x-5)=0}}}
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The value which works here is {{{x=5}}}.


The numbers for the solution are  5, 6, 7.