Question 1124855

{{{(2a^2-b)^6 }}} expand

{{{(2a^2-b)(2a^2-b)(2a^2-b)(2a^2-b)(2a^2-b)(2a^2-b) }}} 

when you multiply all, you will get

{{{64a^12 - 192a^10* b + 240a^8 *b^2 - 160a^6* b^3 + 60a^4* b^4 - 12a^2 *b^5 + b^6}}}

so, fourth term is:{{{- 160 a^6* b^3}}}