Question 1124902
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First consider the shallow end section.  One-fifth of 50m times 1.2m \times 32m.


Add to that a prism with a trapezoidal cross-section.


The area of the trapezoid is four-fifths of 50m times the average of the two depth extremes, namely 1.2m and 3m.  Multiply this area by the width of the pool, namely 32m


Hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (10\ \times\ 1.2\ \times\ 32)\ +\ \(\(\frac{1.2\ +\ 3}{2}\)\ \times\ 40\ \times\ 32\)]


You can do your own arithmetic.

								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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