Question 1124651
vertex form of quadratic equation is 
:
f(x) = a(x-h)^2 +k, where (h,k) is the vertex
:
we are given the vertex (1,3)
:
f(x) = a(x-1)^2 +3
:
we are given point (-2,0) on the curve
:
a(-2-1)^2 +3 = 0
:
9a +3 = 0
:
9a = -3
:
a = -3/9 = -1/3
:
f(x) = (-1/3)(x-1)^2 +3 =
:
(-1/3)(x^2 -2x +1) +3 =
:
-x^2/3 +2x/3 -1/3 + 3 =
:
-x^2/3 +2x/3 +8/3
:
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f(x) = -x^2/3 +2x/3 +8/3
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