Question 101910
The problem is:
2^2x = 8^(x-1) 
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Write both sides to the base 2 as follows:
2^(2x) = (2^3)^(x-1)
2^2x = 2^[3x-3]
Since the bases are the same the exponents are equal.
2x = 3x-3
-x = -3
x = 3
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Cheers,
Stan H.