Question 1124603
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From the condition, 57.8% students have a computer - hence, the rest 100% - 57.8% = 42.2% do not have a computer.


So the probability that the student selected at random has no computer is 0.422.


Then the probability that no one of 8 students selected at random has a computer is  {{{0.422^8}}} = 0.001 (approximately).
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Solved.