Question 1124548
From -2 to 0 with 0 open, the graph is 3x+4, up and to the right, with domain -2 to 0 and range -2 at the left end to 4 open at the right end.  There is an x-intercept at -4/3.
at x=0, y=-3, which adds a point to the range and nothing to the domain.  It is the y-intercept.
at x>0, it is -2x, which makes the range from 0 to - oo for this part, and therefore makes the whole range from -oo to 4 open.  The domain is x from -2 to +oo.

{{{graph(300,300,-2,0,-10,10,3x+4)}}}
{{{graph(300,300,0,5,-5,5,-2x)}}}

At 0, the function is -3, and that is a solid point.  There should be an open point for the two lines at x=0.
The domain is [-2, oo)
The range is (-oo, 4] 
The x-intercept is at (-4/3, 0).
The y-intercept is at (0, -3).
While there is a second "crossing" of the x-axis, it is a jump and not a point.