<PRE><B>Question 1124553</B>
----
FACTOR 6z^2 - 13z + 5 with steps using ac method. Is the answer prime?
----


Just checking different linear factor combinations
{{{6x^2-13x+5=(2x-1)(3x-5)}}}, and no other combination will do this.




----
FACTOR 6x^2 - 4x -5 with steps. Is the answer prime? 
----


Different simple linear factor combinations seem to not give matching results.
Discriminant is  {{{(-4)^2-4*6(-5)=16+120=136}}}, which is not a perfect square; and its square root is not an integer.</PRE>