Question 1124499
Find the value of {{{p}}} so that the line through ({{{p}}},{{{4}}}) and ({{{3}}}, {{{-1}}}) has a slope of {{{-5/8}}}.

given:

point ({{{x[1]}}},{{{y[1]}}})=({{{p}}},{{{4}}})
point ({{{x[2]}}},{{{y[2]}}})=({{{3}}},{{{-1}}})
{{{m=-5/8}}}

use formula or slope:

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}....plug in given values

{{{-5/8=(-1-4)/(3-p)}}}.......solve or {{{p}}}

{{{-5(3-p)=8(-1-4)}}}

{{{-5(3-p)=8(-5)}}}...simplify

{{{-cross(5)(3-p)=8(-cross(5))}}}

{{{3-p=8}}}

{{{3-8=p}}}

{{{p=-5}}}


so, ({{{p}}},{{{4}}})=({{{-5}}},{{{4}}})


check the slope:

({{{-5}}},{{{4}}}) and ({{{3}}}, {{{-1}}}) and see if it has a slope of {{{-5/8}}}


*[invoke slope -5, 4, 3, -1]