Question 1124476
Answer 740789 by josgarithmetic(27564) is WRONG, I double checked it


this is correct answer:


 {{{ (4x+3)^-2 = (49/16)^-1 }}} 

 {{{ 1/(4x+3)^2 =1/ (49/16)^1 }}} 

 {{{ 1/(4x+3)^2 =16/49 }}} 

{{{ 49*1 =16(4x+3)^2}}} 

{{{ 49 =16((4x)^2+2*4x*3+3^2)}}} 

{{{ 49 =16(16x^2+24x+9)}}} 

{{{ 49 =256x^2+384x+144}}} 

{{{ 0 =256x^2+384x+144-49}}} 

{{{ 256x^2+384x+95=0}}} ...factor completely

{{{ 256x^2+304x+80x+95=0}}} ...group

{{{(256x^2+80x)+(304x+95)=0}}}

{{{ 16x(16x+5)+19(16x+5)=0}}}

{{{(16x + 5) (16x + 19) = 0}}}

solutions:

if {{{(16x + 5)  = 0}}}->{{{16x=-5}}}->{{{x=-5/16}}}

if {{{(16x + 19) = 0}}}->{{{16x=-19}}}->{{{x=-19/16}}}