Question 101667
{{{(1/2)x}}} - 2 = {{{(1/3)(x-2)}}}
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The first thing you want to do is get rid of the fractions, multiplying by 6 will do it:
6*{{{(1/2)x}}} - 6(2) = 6*{{{(1/3)(x-2)}}}
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Cancel out the denominators and you have:
3x - 12 = 2(x-2)
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Multiply what's inside the brackets:
3x - 12 = 2x - 4
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3x - 2x = -4 + 12; do some basic algebra
:
1x = 8
or
x = 8
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Substitute 8 for x in the original equation and see if it is true
{{{(1/2)}}}8 - 2 = {{{(1/3)(8-2)}}}
 4 - 2 = {{{1/3}}}*6; confirms our solution
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Did this unconfuse you, any questions?