Question 1124238
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(x,n,p)\ =\ {{n}\choose{x}}\(p\)^x\cdot\(1\,-\,p)^{n\,-\,x}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \mu(x)\ =\ np]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sigma(x)\ =\ \sqrt{np(1\,-\,p)}]


You can do your own arithmetic.  Note *[tex \Large {{n}\choose{r}}] is the combination of *[tex \Large n] things taken *[tex \Large r] at a time. That is: *[tex \Large \frac{n!}{r!(n\,-\,r)!}]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}

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