Question 1124288


 
Rectangle 1

{{{L=12}}}
{{{W=x}}}
{{{A= 12*x}}}

Rectangle 2

{{{L=x-2}}}
{{{W=16}}}
{{{A= (x-2)*16}}}

since given that the rectangles have the same area, we have

{{{ 12*x=(x-2)*16}}}

{{{ 12x=16x-32}}}

{{{ 32=16x-12x}}}

{{{ 32=4x}}}

{{{x=9}}}