Question 1124276
i believe 11.


her father would have to be 6 * 11 = 66


66 and 11 = 77.


you would solve as follows:


you are given that the father is 6 times as old as june.


let F = the father's age.
let J = june's age


the equation for that is F = 6J.


you are given that the sum of their ages is no less than 77.


the equation for that is F + J >= 77


your two equations that need to be solved simultneously are:


F = 6J
F + J >= 77


since F = 6J from the first equation, replace F with 6J in the second equation to get:


6J + J >= 77


combine like terms to getr 7J >= 77


divide both sides of that equation by 7 to get J >= 11.


the youngest june can be is 11 years old.


that makes her father 6 * 11 = 66


that makes the sum of their ages equal to 66 + 11 = 77.