Question 101853
I'm assuming you mean a standard 52 card deck and your question is the probability of drawing either a 3 Clubs{{{P[1]}}} or 6 Diamonds {{{P[2]}}}on one draw. The probability of drawing a 3 Clubs alone and the probability of drawing a 6 Diamonds alone are both equal{{{P[1]=P[2]=1/52}}}. By putting them together, you add their probabilities. So the probability of drawing either a 3 Clubs or 6 Diamonds on one draw is 2/52{{{P[3]=1/52+1/52=2/52}}}.