<PRE><B>Question 101853</B>
what is the probability of drawing 3 clubs or a six of diamonds?
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Those are mutually exclusive events so
P(3 clubs or six of diamonds) = P(3clubs)+P(6 of diamonds)
= 13C3/52C3 + 1/52
= 286/22100  + 1/52
= 0.13 + 0.19
= 0.32
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Cheers,
Stan H.</PRE>