Question 1124065

a pilot flew a jet from point a to point b, a distance of 2500 mi. on the return trip, the average speed was 20% faster than the outbound speed. the round-trip took 9h and 10min. what was the speed from point a to point b?
<pre>Let outbound speed be S
Then return speed  = 1.2S
Then we get the following TIME equation: {{{matrix(1,5, "2,500"/S, "+", "2,500"/(1.2S), "=", 9&1/6)}}}_______{{{matrix(1,5, "2,500"/S, "+", "2,500"/(1.2S), "=", 55/6)}}}
12(2,500) + 10(2,500) = 110S -------- Multiplying by LCD, 12S
22(2,500) = 110S
S, or outbound speed = {{{highlight_green(matrix(1,4, 22("2,500")/110, "=", 500, mph))}}}