Question 1124069
Shelias age is two years more than twice Nicole’s age. The sum of their ages is the same as Steve’s age. If Steve’s age is ten years less than five times Nicole’s age, find the age of each. 
<pre>Let Nicole's be N
Then Sheila's = 2N + 2 
Also, Steve's is: N + 2N + 2, or 3N + 2
We then get: 3N + 2 = 5N - 10
3N - 5N = - 10 - 2
- 2N = - 12
N, or Nicole is: {{{highlight_green(matrix(1,4, (- 12)/(- 2), "=", 6, years-old))}}}
Sheila is: 2(6) + 2, or 14 years-old
Steve is: 3(6) + 2 = 20 years-old
That's it!! Nothing COMPLEX!!