Question 1123940
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<pre>
Let x = how much money was invested at 13%.

Then the amount invested at 4% is  (6100-x) dollars.


Interest from the 13% account = 0.13*x dollars.

Interest from the 4% account = 0.04*(6100-x).


Your equation is


    <U>interest</U> + <U>interest</U>      = <U>total combined interest</U>,    or


    0.13x    + 0.04*(6100-x) = 532    dollars.


    0.13x + 0.04*6100 - 0.04x = 532

    (0.13 - 0.04)x = 532 - 0.04*6100

    x = {{{(532 - 0.04*6100)/(0.13-0.04)}}} = 3200.


<U>Answer</U>.  $3200 were invested at 13% and the rest,  6100-3200 = 2900 dollars were invested at 4%.

         <U>Check</U>.  0.13*3200 + 0.04*2900 = 532  dollars.    ! Correct !
</pre>

Solved.


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It is a standard and typical problem on investments.


If you need more details,  &nbsp;or if you want to see other similar problems solved by different methods, &nbsp;look into the lesson 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.