Question 1123884

Find the largest angle of a triangle where the larger is 20° greater than the smallest and the largest is twice the smallest angle.
<pre>Let larger be L
Then smallest = {{{L/2}}}
Also, larger (middle) = {{{L/2 + 20}}}
We then get: {{{matrix(1,3, L + L/2 + L/2 + 20, "=", 180)}}}
{{{matrix(1,3, L + 2L/2, "=", 160)}}}
{{{highlight_green(system(matrix(1,3, L + L, "=", 160), matrix(1,3, 2L, "=", 160), matrix(1,8, L, or, larger, angle, "=", 160/2, "=", 80^o)))}}}