Question 1123854

zeros:{{{ x[1]=3-3i}}},{{{x[2]=3+3i}}}, and {{{x[3]=3}}}

to find equation, use product of factors

{{{(x-x[1])(x-x[2])(x-x[3])}}}...substitute given zeros

{{{(x-(3-3i))(x-(3+3i))(x-3)}}}

{{{(x-3+3i)(x-3-3i)(x-3)}}}

{{{(x^2-3x-cross(3xi)-3x+9+cross(9i)+cross(3xi)-cross(9i)-9i^2)(x-3)}}}

{{{(x^2-6x+9+9*1)(x-3)}}}

{{{(x^2-6x+9+9)(x-3)}}}

{{{(x^2-6x+18)(x-3)}}}

{{{x^3-6x^2+18x -3x^2+18x-54}}}

{{{x^3-9x^2+36x-54}}}